1. The interaction of copper hydroxide with carbonic acid is described by the reaction equation:
Cu (OH) 2 + H2CO3 = CuCO3 + 2H2O;
2.Calculate the chemical amount of copper hydroxide:
n (Cu (OH) 2) = m (Cu (OH) 2): M (Cu (OH) 2);
M (Cu (OH) 2) = 64 + 2 * 17 = 98 g / mol;
n (Cu (OH) 2) = 9.8: 98 = 0.1 mol;
3. Determine the amount of water formed:
n (H2O) = n (Cu (OH) 2) * 2 = 0.1 * 2 = 0.2 mol;
4.Calculate the mass of water:
m (H2O) = n (H2O) * M (H2O) = 0.2 * 18 = 3.6 g.
Answer: 3.6 g.
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