# What mass of zinc fluoride is formed by the interaction of zinc weighing 16.5 g with an excess of fluorine?

July 31, 2021 | education

| Given:

m (Zn) = 16.5 g

To find:

m (ZnF2) -?

Solution:

1) Write the equation of a chemical reaction:

Zn + F2 => ZnF2;

2) Calculate the molar masses of Zn and ZnF2:

M (Zn) = Mr (Zn) = Ar (Zn) = 65 g / mol;

M (ZnF2) = Mr (ZnF2) = Ar (Zn) * N (Zn) + Ar (F) * N (F) = 65 * 1 + 19 * 2 = 103 g / mol;

3) Calculate the amount of substance Zn:

n (Zn) = m (Zn) / M (Zn) = 16.5 / 65 = 0.25 mol;

4) Determine the amount of ZnF2 substance:

n (ZnF2) = n (Zn) = 0.25 mol;

5) Calculate the mass of ZnF2:

m (ZnF2) = n (ZnF2) * M (ZnF2) = 0.25 * 103 = 25.8 g.

Answer: The mass of ZnF2 is 25.8 g.

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