What path does the car manage to cover in the first 10 off the path with an engine thrust of 1000 N

What path does the car manage to cover in the first 10 off the path with an engine thrust of 1000 N and a rhenium coefficient of 0.5? machine weight 500 kg.

Given: t (duration of movement of the machine) = 10 s; Ft (engine thrust force) = 1000 N; μ (coefficient of friction) = 0.05; m (mass of the machine in question) = 500 kg.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

The path that the machine under consideration will have time to pass in the first 10 s is calculated by the formula: S = V0 * t + 0.5 * a * t ^ 2 = 0 * t + 0.5 * (F / m) * t2 = 0, 5 * ((Ft – Fc) / m) * t ^ 2 = 0.5 * ((Ft – μ * m * g) / m) * t2.

Let’s perform the calculation: S = 0.5 * ((1000 – 0.05 * 500 * 10) / 500) * 10 ^ 2 = 75 m.