What pressure does a 6m3 marble column exert on the ground if its base area is 1.5m2?

To find out the pressure on the ground exerted by the specified marble column, we use the formula: P = Fт / S = mк * g / S = ρm * V * g / S, where ρm is the density of the marble (const; ρm = 2700 kg / m3); V is the volume of the specified column (V = 6 m3); g – acceleration due to gravity (const; g = 9.81 m / s2); S – base area (S = 1.5 m2).

Let’s perform the calculation: P = ρm * V * g / S = 2700 * 6 * 9.81 / 1.5 = 105948 Pa ≈ 106 kPa.

Answer: The specified marble column must exert a pressure of 106 kPa.