What pressure is produced by a table with a floor mass of 20 kg, if the area of each of the four legs of the table is 10 cm2.

To find the pressure produced by the specified table on the floor, you must use the formula: P = Fт / S = m * g / (n * Sн).

Data: m is the mass of the specified table (m = 20 kg); g – acceleration of gravity (g = 9.81 m / s2); n is the number of legs (n = 4 pcs.); Sн – support area of one leg (Sн = 10 cm2 = 10 * 10 ^ -4 m2).

Calculation: P = m * g / (n * Sн) = 20 * 9.81 / (4 * 10 * 10 ^ -4) = 49.05 * 10 ^ 3 Pa.

Answer: The pressure from the side of the specified table is 49.05 kPa.



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