Organic matter С3Н7ОН – propanol. Let us write down the reaction equations for the saturated monohydric alcohols.
2С3Н7ОН + 9О2 = 6СО2 + 8Н2О – combustion reaction, carbon dioxide and water are released;
С3Н7ОН + HCl = C3H7Cl + H2O – exchange, propane chloride is released;
С3Н7ОН + СН3СООН = СН3СОО – С3Н7 + Н2О – esterification, acetic propionic ether is formed;
С3Н7ОН = Н2О + Н3С – СН = СН2 – dehydration, propylene was obtained;
2С3Н7ОН + 2Na = 2C3H7ONa + H2 – substitutions, sodium propionate is released;
C3H7OH + C3H7OH = C3H7 – O – C3H7 + H2O – intermolecular hydration;
С3Н7ОН + CuO = Cu + H2O + H3C – CH2 – COH – oxidation of propanol, obtained propanal.
These reactions confirm the high chemical activity of propanol and are possible due to the functional group – OH.
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