What should be the length of an inclined plane with a height of 1 m for uniform lifting of a load weighing 90 kg along it under the action of 180 H.
h = 1 m.
m = 90 kg.
g = 9.8 m / s ^ 2.
F = 180 N.
For uniform lifting of a load, according to 1 Newton’s law, on an inclined plane, the force F with which the load is pulled must be equal to the projection of the gravity force on the plane along which the load is pulled.
F = m * g * sin α, where ∠α is the angle between the horizon and the inclined plane.
sin α = h / S.
F = m * g * h / S.
S = m * g * h / F.
S = 90 kg * 9.8 m / s ^ 2 * 1 m / 180 N = 4.9 m.
Answer: the length of the inclined plane is S = 4.9 m.
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