What temperature will be established in the vessel if the mass of ice is 200 grams
March 23, 2021 | education
| What temperature will be established in the vessel if the mass of ice is 200 grams, the mass of water is 2 kg, and the initial water temperature is 30 degrees?
Q1 + Q2 = Q3.
We assume that ice is at a temperature of 0 ° C.
Q1 (ice melting) = λ * m1, where λ = 3.4 * 10 ^ 5 J / kg, m1 = 200 g = 0.2 kg.
Q2 (heating): Q2 = C * m1 * (t3 – t1), where C = 4200 J / (kg * K), t3 is the steady-state temperature, t1 = 0 ° C.
Q3 (cooling): Q2 = С * m2 * (t2 – t3), where m2 = 2 kg, t2 = 30 ° С.
λ * m1 + С * m1 * (t3 – t1) = С * m2 * (t2 – t3).
3.4 * 105 * 0.2 + 4200 * 0.2 * (t3 – 0) = 4200 * 2 * (30 – t3).
68000 + 840t3 = 252000 – 8400t3.
9240t3 = 184000.
t3 = 19.91 ° C.
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