What voltage must be applied to a lead wire 2 m long so that the current in the wire is 2 A? Wire cross-sectional area 0.3 mm2
Initial data: l (lead wire length) = 2 m; I (required current strength) = 2 A; S (cross-sectional area of lead wire) = 0.3 mm2.
Reference data: ρ (lead resistivity, n.o.) = 0.21 Ohm * mm2 / m.
1) Let’s calculate the resistance of the lead wire: R = ρ * l / S = 0.21 * 2 / 0.3 = 1.4 Ohm.
2) Determine the voltage that needs to be applied to the wire: U = I * R = 2 * 1.4 = 2.8 V.
Answer: A voltage of 2.8 V must be applied to the lead wire.
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