What volume and mass of hydrogen is released during the interaction of 6.9 g of sodium and water?

1. We are given the following chemical equation with the assigned coefficients:

2Na + 2H2O = 2NaOH + H2.

2. Let’s find the amount of sodium substance:

n (Na) = m / M = 6.9 / 23 = 0.3 mol.

3. According to the equation, we make up the proportion:

n (Na) / n (H2) = 2/1 = 0.3 / 0.15; therefore n (H2) = 0.15 mol.

4. Let’s find the mass H2:

m (H2) = 0.15g.

5. Let’s find the volume of H2:

V (H2) = 0.15 * 22.4 = 3.36l.

Answer: V (H2) = 3.36L; m (H2) = 0.15g.