1. We are given the following chemical equation with the assigned coefficients:
2Na + 2H2O = 2NaOH + H2.
2. Let’s find the amount of sodium substance:
n (Na) = m / M = 6.9 / 23 = 0.3 mol.
3. According to the equation, we make up the proportion:
n (Na) / n (H2) = 2/1 = 0.3 / 0.15; therefore n (H2) = 0.15 mol.
4. Let’s find the mass H2:
m (H2) = 0.15g.
5. Let’s find the volume of H2:
V (H2) = 0.15 * 22.4 = 3.36l.
Answer: V (H2) = 3.36L; m (H2) = 0.15g.
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