What volume of carbon dioxide will be released when burning 0.4 mol of 1-propanol?

2С3Н7ОН + 9О2 = 6СО2 + 8Н2О.

X = 0.4 * 6: 2 = 1.2 mol of CO2.

V (CO2) = 1.2 * 22.4 = 26.88 liters.

Therefore, 26.88 liters of CO2 will be released.

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