What volume of gas will be released when 200 g of 49% sulfuric acid solution interacts with sodium sulfite?
| July 23, 2021 | education
The interaction of sodium sulfite with sulfuric acid is equimolar, how many moles of salt react, so many moles of sulfur dioxide will be released:
Na2SO3 + H2SO4 = SO2 + H2O + Na2SO4.
Let’s calculate the amount of substance using the value of molar masses M and the data of the problem.
M H2SO4 is 98 g, which means that it entered into a reaction: ((200 * 49%) / 100%) / 98 = 1 mol.
The volume of the evolved SO2 gas is equal to:
22.4 l / mol * 1 mol = 22.4 l.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
