What volume of gaseous hydrogen chloride HCl is formed in the reaction of chlorine Cl₂ with a mass of 71 g and hydrogen H₂ with a mass of 2 g?
H2 + Cl2 = 2 HCl
Let’s find the amount of reactants:
n (H2) = m (H2) / M (H2) = 2/2 = 1 mol;
n (Cl2) = 71/71 = 1 mol;
Substances are taken in stoichiometric proportions.
n (HCl) = 2n (H2) = 2 mol;
V (HCl) = n (HCl) × VM = 2 × 22.4 = 44.8 liters.
Answer: V (HCl) = 44.8 liters.
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