.What volume of hydrogen can be obtained if 92 grams of sodium reacted with water?

2Na + 2H2O = 2NaOH + H2.
It can be seen from the reaction equation that to obtain 1 mole of hydrogen, the participation of 2 moles of sodium is required. Thus, hydrogen will be released:
(92 g: 23 g / mol) * 1/2 * 22.4 L / mol = 44.8 L.

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