What volume of hydrogen chloride is formed by the interaction of 3.01 times 10 ^ 23 hydrogen molecules with a sufficient amount of chlorine?
We find out the amount of hydrogen – there are 6.02 * 10 ^ 23 molecules in 1 mole of a substance (Avogadro’s number):
3.01 * 10 ^ 23 / 6.02 * 10 ^ 23 = 0.5 (mol).
Equation of the share:
H2 + Cl2 = 2HCl.
From the reaction equation:
1 mol H2 -> 2 mol HCl
0.5 mol H2 -> x mol HCl.
x = 1/2 * 0.5 = 1 (mol).
1 mole of gaseous substance at normal conditions occupy a volume of 22.4 liters. Those. the volume of HCl is 22.4 liters.
Answer: 22.4 liters.
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