What volume of hydrogen is required for the complete reduction of 24 g CuO?
August 31, 2021
m (CuO) = 24 g
V (H2) -?
1) H2 + CuO => Cu + H2O;
2) M (CuO) = Mr (CuO) = Ar (Cu) * N (Cu) + Ar (O) * N (O) = 64 * 1 + 16 * 1 = 80 g / mol;
3) n (CuO) = m (CuO) / M (CuO) = 24/80 = 0.3 mol;
4) n (H2) = n (CuO) = 0.3 mol;
5) V (H2) = n (H2) * Vm = 0.3 * 22.4 = 6.72 liters.
Answer: The volume of H2 is 6.72 liters.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.