1.Let’s find the amount of iron (II) sulfide – FeS.
M (FeS) = 56 + 32 = 88 g / mol.
n = m: M
n = 0.88 g: 88 g / mol = 0.01 mol.
2. Let’s compose the equation of the reaction between iron sulfide and hydrochloric acid.
FeS + 2HCl = FeCl2 + H2S.
According to the reaction equation, for 1 mole of iron sulfide, there is 1 mole of gas – hydrogen sulfide, that is, their quantitative ratios are 1: 1. Then the amount of iron sulfide substance will be the same with the amount of hydrogen sulfide substance.
n (H2S) = 0.01 mol.
Let’s find the volume by the formula:
V = n Vn, where Vn is the molar volume of the gas, equal to 22.4 l / mol.
V = 22.4 L / mol x 0.01 mol = 0.224 L.
Answer: V = 0.224 l.
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