What volume of hydrogen will be released if 8 g of calcium is placed in water with a mass of 40 g?

The reaction of calcium with water is described by the following chemical reaction equation:

Ca + 2H2O = Ca (OH) 2 + H2;

One mole of calcium reacts with two moles of water. This produces one mole of hydroxide and one mole of hydrogen.

Let’s find the amount of the substance in 8 grams of calcium.

M Ca = 40 grams / mol;

N Ca = 8/40 = 0.2 mol;

Let’s find the amount of substance in 40 grams of water.

M H2O = 2 + 16 = 18 grams / mol;

N H2O = 40/18 = 2.22 mol;

0.2 mol of calcium will react with 0.4 mol of water. This will release 0.2 mol of hydrogen.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

V H2 = 0.2 x 22.4 = 4.48 liters;