What volume of hydrogen will be released under the action of 32.5 g of zinc on sulfuric acid if the hydrogen yield is 95%?

1. Let’s compose the equation of the reaction proceeding under the action of zinc on sulfuric acid:

Zn + H2SO4 = ZnSO4 + H2 ↑;

2. find the chemical amount of zinc:

n (Zn) = m (Zn): (Zn) = 32.5: 65 = 0.5 mol;

3. Determine the theoretical amount of evolved hydrogen:

ntheor (H2) = n (Zn) = 0.5 mol;

4.calculate the theoretical volume of hydrogen:

Vtheor (H2) = ntheor (H2) * Vm = 0.5 * 22.4 = 11.2 liters;

5.Calculate the practical volume of hydrogen produced:

Vpract (H2) = Vtheor (H2) * ν = 11.2 * 0.95 = 10.64 liters.

Answer: 10.64 liters.




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