What volume of hydrogen will be released upon the interaction of 20 g of hydrochloric acid and 34 g of copper?

The reaction of copper with hydrogen chloride is described by the following chemical reaction equation.

Cu + 2HCl = CuCl2 + H2;

One mole of copper reacts with two moles of hydrogen chloride. This produces one mole of hydrogen gas. Let’s determine the amount of the substance, which is contained in 34 grams of copper and 20 grams of 36.5% hydrogen chloride.

M Cu = 64 grams / mol;

The amount of metallic copper substance will be:

N Cu = 34/64 = 0.531 mol;

M HCl = 1 + 35.5 = 36.5 grams / mol;

m HCl = 20 grams;

The amount of hydrogen chloride substance will be:

N HCl = 20 / 36.5 = 0.548 mol;

0.548 / 2 = 0.274 mol of copper will react with 0.548 mol of hydrogen chloride. This produces 0.274 mol of hydrogen gas.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Determine the volume of hydrogen gas.

V H2 = 0.274 x 22.4 = 6.138 liters;

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