What volume of hydrogen will be released when zinc is dissolved in 730 g of 20% hydrochloric acid solution?

The reaction of zinc with hydrochloric acid is described by the following chemical reaction equation.

Zn + 2HCl = ZnCl2 + H2;

One mole of zinc reacts with two moles of hydrochloric acid. This produces one mole of hydrogen. Determine the amount of substance contained in 730 grams of 20% hydrochloric acid solution.

M HCl = 1 + 35.5 = 36.5 grams / mol;

m HCl = 730 x 0.2 = 146 grams;

N HCl = 146 / 36.5 = 4 mol;

Reaction with 4 moles of hydrochloric acid with sufficient zinc will produce 2 moles of hydrogen.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Let’s determine the volume of hydrogen.

V H2 = 2 x 22.4 = 44.8 liters;

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