What volume of water can be heated from 20 degrees to boiling, giving it 1.6 * 8 MJ of heat?

Given:

Q – amount of heat 1.6 * 8 MJ = 12.8 MJ = 12,800,000 J;

с – specific heat capacity for water 4 200 J / kg * ° С;

Δt – temperature difference 100 ° С – 20 ° С = 80 ° С.

In order to find out what volume of water heated from 20 ° to 100 ° is required, informing it of 1.6 * 8 MJ = 12.8 MJ of heat.

Let’s apply to the solution the formula for calculating the amount of heat:

Q = c * m * Δt;

Let us express the mass:

m = Q / cΔt;

Substitute the values and calculate:

m = 12 800 000 / (4 200 * 80) = 12 800 000/336000 ≈ 38 kg.

Water volume:

V = m / p;

m – weight 38 kg.

p is the density of 1,000 kg / m ^ 3.

V = 38/1000 = 0.038 m ^ 3.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.