What was the average force of water resistance to the movement of the steamer if it consumed 6.5 tons of coal
August 31, 2021 | education|
What was the average force of water resistance to the movement of the steamer if it consumed 6.5 tons of coal within 3 days at an average speed of 10 km / h? Motor efficiency 10%
Data: t (duration of the steamer movement) = 3 days. (in SI t = 259200 s); V (steamer speed) = 10 km / h (in SI V = 2.78 m / s); m (mass of coal consumed) = 6.5 t (in SI m = 6500 kg); η (motor efficiency) = 10% (0.1).
Constants: q (specific heat of combustion of coal) = 2.7 * 10 ^ 7 J / kg.
We express the average water resistance force from the formula: η = Ap / Q = Fc * S / (q * m) = Fc * V * t / (q * m), whence Fc = η * q * m / (V * t) …
Calculation: Fc = 0.1 * 2.7 * 10 ^ 7 * 6500 / (2.78 * 259200) = 24 375 N.
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