What work does the electric current do in the electric motor in 30 minutes, if the current in the circuit is 0.5 A, and the voltage at the motor terminals is 12 V?
The work of an electric current in an electric motor can be calculated using the formula:
A = I * U * t, where I is the value of the current in the circuit (I = 0.5 A), U is the voltage at the terminals of the electric motor (U = 12 V), t is the operating time of the electric current (t = 30 min = 30 * 60 = 1800 s).
A = I * U * t = 0.5 * 12 * 1800 = 10800 J = 10.8 * 10 ^ 3 J = 10.8 kJ.
Answer. Electric current will do useful work of 10.8 kJ.
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