When 128 g of calcium carbide interacted with water weighing 73 g, acetylene with a volume of 40 liters was released.

When 128 g of calcium carbide interacted with water weighing 73 g, acetylene with a volume of 40 liters was released. Determine the acetylene yield as a percentage of the theoretically possible.

When calcium carbide interacts with water, acetylene and calcium hydroxide are synthesized. The reaction is described by the following equation.

CaC2 + 2H2O = Ca (OH) 2 + C2H2;

From 1 mole of calcium carbide, 1 mole of acetylene is synthesized.

Let’s calculate the available amount of calcium carbide substance.

To do this, we divide the mass of the substance by its molar weight.

M CaC2 = 40 + 12 x 2 = 64 grams / mol;

N CaC2 = 128/64 = 2 mol;

The amount of water is:

M H2O = 2 + 16 = 18 grams / mol;

N H2O = 73/18 = 4.056 mol;

Let’s calculate the volume of 2 mol of acetylene.

To do this, multiply the amount of substance by the volume of 1 mole, which is 22.4 liters.

V C2H2 = 2 x 22.4 = 44.8 liters;

The reaction yield will be K = 40 / 44.8 = 0.893 = 89.3%;



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.