When 13.5 g of aluminum are combined with oxygen, 547 kJ of heat is released

When 13.5 g of aluminum are combined with oxygen, 547 kJ of heat is released. Write a thermochemical equation for this reaction.

1.we write down the reaction equation:

4Al + 3O2 = 2Al2O3 + x kJ;

2.Calculate the chemical amount of aluminum:

n (Al) = m (Al): M (Al) = 13.5: 27 = 0.5 mol;

3.based on the writing of the equation for the interaction of aluminum with oxygen, we will compose the proportion:

combustion of 4 mol of Al produces x kJ of heat;

and during combustion of 0.5 mol of Al – 547 kJ;

4.calculate x:

x = 4 * 547: 0.5 = 4376 kJ.

Answer: 4Al + 3O2 = 2Al2O3 + 4376 kJ.