When 13.5 g of aluminum are combined with oxygen, 547 kJ of heat is released. Write a thermochemical equation for this reaction.
1.we write down the reaction equation:
4Al + 3O2 = 2Al2O3 + x kJ;
2.Calculate the chemical amount of aluminum:
n (Al) = m (Al): M (Al) = 13.5: 27 = 0.5 mol;
3.based on the writing of the equation for the interaction of aluminum with oxygen, we will compose the proportion:
combustion of 4 mol of Al produces x kJ of heat;
and during combustion of 0.5 mol of Al – 547 kJ;
x = 4 * 547: 0.5 = 4376 kJ.
Answer: 4Al + 3O2 = 2Al2O3 + 4376 kJ.
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