When 50 g of a 40% solution of iron sulfate (3) interacted with a solution of sodium

| August 31, 2021 | education

When 50 g of a 40% solution of iron sulfate (3) interacted with a solution of sodium hydroxide, a precipitate was formed. Calculate the mass of the sediment.

1. Let’s compose the reaction equation:

Fe2 (SO4) 3 + 6NaOH = 2Fe (OH) 3 ↓ + 3Na2SO4;

2. find the mass of ferrous sulfate (3):

m (Fe2 (SO4) 3) = w (Fe2 (SO4) 3) * m (solution);

m (Fe2 (SO4) 3) = 0.4 * 50 = 20 g;

3.Calculate the chemical amount of ferrous sulfate:

n (Fe2 (SO4) 3) = m (Fe2 (SO4) 3): M (Fe2 (SO4) 3);

M (Fe2 (SO4) 3) = 2 * 56 + 3 * 32 + 4 * 3 * 16 = 400 g / mol;

n (Fe2 (SO4) 3) = 20: 400 = 0.05 mol;

4. find the amount of iron hydroxide:

n (Fe (OH) 3) = n (Fe2 (SO4) 3) * 2 = 0.05 * 2 = 0.1 mol;

5.Calculate the mass of the sediment:

m (Fe (OH) 3) = n (Fe (OH) 3) * M (Fe (OH) 3);

M (Fe (OH) 3) = 56 + 3 * 17 = 107 g / mol;

m (Fe (OH) 3) = 0.1 * 107 = 10.7 g.

Answer: 10.7 g.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.