When 9.9 g of zinc hydroxide interacted with sulfuric acid, 12.88 g of salt was formed. Find the yield of the reaction product.
1. Let’s compose the equation for the reaction of zinc hydroxide with sulfuric acid:
Zn (OH) 2 + H2SO4 = ZnSO4 + 2H2O;
2. Calculate the chemical amount of zinc hydroxide:
n (Zn (OH) 2) = m (Zn (OH) 2): M (Zn (OH) 2);
M (Zn (OH) 2) = 65 + 2 * 17 = 99 g / mol;
n (Zn (OH) 2) = 9.9: 99 = 0.1 mol;
3. Determine the theoretical amount of zinc sulfate:
ntheor (ZnSO4) = n (Zn (OH) 2) = 0.1 mol;
4. Let’s calculate the theoretical mass of salt:
mtheor (ZnSO4) = ntheor (ZnSO4) * M (ZnSO4);
M (ZnSO4) = 65 + 32 + 4 * 16 = 161 g / mol;
mtheor (ZnSO4) = 0.1 * 161 = 16.1 g;
5. Let’s find the output of the product:
ν = mp (ZnSO4): mtheor (ZnSO4) = 12.88: 16.1 = 0.8 or 80%.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.