When a force of 20n is applied to the support, the pressure is 200 pascals at what time the pressure of 40n

When a force of 20n is applied to the support, the pressure is 200 pascals at what time the pressure of 40n changes on the support.

Data: Fн (initial force acting on the support) = 20 N; Pн (initial pressure) = 200 Pa; Fк (considered pressure force) = 40 N.

1) Determine the pressure with an acting force of 40 N: Fn / Pn = S = Fk / Pk, whence Pk = Fk * Pn / Fn = 40 * 200/20 = 400 Pa.

2) Let’s calculate the change in pressure: k = Pк / Pн = 400/200 = 2 times.

Answer: The pressure on a given support will double.



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