When combusting hydrocarbons with a mass of 29 g, 88 g of CO2 and 45 g of H2O were formed.

When combusting hydrocarbons with a mass of 29 g, 88 g of CO2 and 45 g of H2O were formed. Its relative density in H2 is 2. Find the formula.

Let us write the reaction equation for the combustion of hydrocarbons:

CxHy + O2 → CO2 + H2O;

Mr (C) = 12; Mr (CO2) = 12 + 16 * 2 = 44;

m (C) = 12/44 * 88 = 24 g;

Mr (H2) = 1 * 2 = 2; Mr (H20) = 1 * 2 + 16 = 18;

m (H) = 2/18 * 45 = 5 g;

x / y = 24/12: 5/1 = 2: 5;

C2H5 is the simplest formula;

Mr (C2H5) = 24 + 5 = 29;

Mr ist. = 29 * 2 = 58;

Mr ist / Mr (C2H5) = 58/29 = 2;

C4H10 – HC formula.



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