When connecting a resistance of 15 ohms to a battery, the ammeter in the circuit shows 1 A. If the same source

When connecting a resistance of 15 ohms to a battery, the ammeter in the circuit shows 1 A. If the same source is closed with a resistance of 8 ohms, the ammeter will show 1.8 A. Find the EMF of the battery and its internal resistance. Draw a diagram.

In this case, the internal resistance of the source and the load resistance will be connected in series, we write Ohm’s law for such a circuit:

I = U / (R + r), where I is the current strength, U is the EMF of the battery, R is the load resistance, r is the internal resistance of the source. Substituting the data for the first and second cases, we get the system:

U / (15 + r) = 1;

U / (8 + r) = 1.8.

U = (15 + r).

(15 + r) / (8 + r) = 1.8;

15 + r = 1.8r + 14.4;

r = 0.6 / 0.8 = 0.75 ohm.

Then:

U = 1 * (15 + 0.75) = 15.75 V.




One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.

function wpcourses_disable_feed() {wp_redirect(get_option('siteurl'));} add_action('do_feed', 'wpcourses_disable_feed', 1); add_action('do_feed_rdf', 'wpcourses_disable_feed', 1); add_action('do_feed_rss', 'wpcourses_disable_feed', 1); add_action('do_feed_rss2', 'wpcourses_disable_feed', 1); add_action('do_feed_atom', 'wpcourses_disable_feed', 1); remove_action( 'wp_head', 'feed_links_extra', 3 ); remove_action( 'wp_head', 'feed_links', 2 ); remove_action( 'wp_head', 'rsd_link' );