When lightning struck, an electric charge of 10 C was transferred from the cloud to the ground. What work was done by the forces of the electric field, if there was a voltage of 1 million volts between the beginning and the end of the lightning? To what height above the surface of the Earth could a person weighing 100 kg be lifted due to the energy of the electric field released by such a lightning strike?
q = 10 Cl.
U = 1 * 10 ^ 6 V.
g = 10 m / s2.
m = 100 kg.
The work of the electric field A on the movement of the electric charge q is determined by the formula: A = q * U, where U is the voltage between the initial and final position of the charge.
A = 10 C * 1 * 10 ^ 6 B = 1 * 10 ^ 7 J.
The potential energy of a person En with a mass m raised to a height h is determined by the formula: En = m * g * h, where g is the acceleration of gravity.
A = En.
A = m * g * h.
h = A / m * g.
h = 1 * 10 ^ 7 J / 100 kg * 10 m / s2 = 10000 m = 10 km.
Answer: the forces of the electric field did the work A = 1 * 10 ^ 7 J, a person can be raised to a height of h = 10 km.
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