When the bodies interact, one of them, having come into motion, passed to a stop of 0.5

When the bodies interact, one of them, having come into motion, passed to a stop of 0.5 m and the other 1.5 m. Which of them has a large mass.

Given:

S1 = 0.5 meters – the path taken by the first body before stopping after interaction;

S2 = 1.5 meters – the path taken by the second body to the stop.

It is required to determine which of the two bodies has a large mass.

We believe that the bodies moved during the same time t, and also that they interacted with the same force F. Since, according to the condition of the problem, the bodies were at rest before the interaction, we will find the accelerations that the bodies receive as a result of interaction:

a1 = 2 * S1 / t ^ 2 = 2 * 0.5 / t ^ 2 = 1 / t ^ 2 = 1 * t ^ -1.

a2 = 2 * S2 / t ^ 2 = 2 * 1.5 / t ^ 2 = 3 / t ^ 2 = 3 * t ^ -1.

Then the masses of the bodies will be equal:

m1 = F / a1 = F / 1 * t ^ -1 = F * t ^ 2.

m2 = F / a2 = F / 3 * t ^ -1 = F * t ^ 2/3.

Since F * t ^ 2> F * t ^ 2/3, the mass of the first body is greater.

Answer: the mass of the first body is greater than the mass of the second.