When the sled is moving through the snow, a team of dogs can operate with a maximum force of 0.5 kN. What mass of a sled with a load can the team move if the coefficient of friction is 0.1?
Ft = 0.5 kN = 500 N.
g = 9.8 m / s2.
μ = 0.1.
4 forces act on a sled with a load:
traction force of dogs Ft, directed in the direction of movement;
friction force Ftr directed in the opposite direction of motion;
gravity m * g directed vertically downward;
snow reaction force N directed vertically upwards.
Ft = Ftr.
N = m * g.
The friction force Ffr is determined by the formula: Ffr = μ * N = μ * m * g.
Fт = μ * m * g.
m = Fт / μ * g.
m = 500 N / 0.1 * 9.8 m / s2 = 510 kg.
Answer: a team of dogs can pull a load weighing m = 510 kg.
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