When the sled is moving through the snow, a team of dogs can operate with a maximum force of 0.5 kN.

When the sled is moving through the snow, a team of dogs can operate with a maximum force of 0.5 kN. What mass of a sled with a load can the team move if the coefficient of friction is 0.1?

Ft = 0.5 kN = 500 N.

g = 9.8 m / s2.

μ = 0.1.

m -?

4 forces act on a sled with a load:

traction force of dogs Ft, directed in the direction of movement;

friction force Ftr directed in the opposite direction of motion;

gravity m * g directed vertically downward;

snow reaction force N directed vertically upwards.

Ft = Ftr.

N = m * g.

The friction force Ffr is determined by the formula: Ffr = μ * N = μ * m * g.

Fт = μ * m * g.

m = Fт / μ * g.

m = 500 N / 0.1 * 9.8 m / s2 = 510 kg.

Answer: a team of dogs can pull a load weighing m = 510 kg.



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