When the voltage at the ends of the conductor is 2 V, the current in the conductor is 0.5 A. What will the current in the conductor be if the voltage at its ends increases to 4 V? If the voltage at its ends decreases to 1 V?
Data: U (initial voltage at the ends of the conductor) = 2 V; I (constant current) = 0.5 A; the resistance of the conductor will be constant.
1) The current in the conductor with an increase in voltage to 4 V (U1 = 4 V): U / I = U1 / I1, whence I1 = U1 * I / U = 4 * 0.5 / 2 = 1 A.
2) The current in the conductor when the voltage decreases to 1 V (U2 = 1 V): U / I = U2 / I2, whence I2 = U2 * I / U = 1 * 0.5 / 2 = 0.25 A.
Answer: At a voltage of 4 V and 1 V, the current in the conductor is 1 A and 0.25 A, respectively.
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