When welding titanium, the temperature of the shielding gas (argon) increased to 391 ° C. Determine the root mean square velocity of argon molecules at this temperature?
Initial data: T (absolute temperature of argon) = 664 K (391 ºС).
Constants: R (universal gas constant) = 8.31 J / (mol * K); M (molar mass of argon) ≈ 0.04 kg / mol.
Determine the root-mean-square velocity of argon molecules by the formula: υav. = √ (3R * T / M).
Let’s calculate: υср. = √ (3 * 8.31 * 664 / 0.04) = 643.3 m / s.
Answer: At a temperature of 391 ºС, the mean square velocity of argon molecules will be 643.3 m / s.
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