With a 4-fold increase in body weight, what does its kinetic energy do?

Given:

m1 is the initial body weight;

m2 = 4 * m1 – the body weight was doubled.

It is required to determine E2 / E1 – the change in kinetic energy.

Since the condition of the problem is not specified, we assume that the speed of the body is constant and equal to v. Then:

The kinetic energy in the first case will be equal to:

E1 = m * v ^ 2/2.

The kinetic energy in the second case will be equal to:

E2 = m ^ 2 * v ^ 2/2 = 4 * m1 * v ^ 2/2.

E2 / E1 = (4 * m1 * v ^ 2/2) / (m * v ^ 2/2) = 4, that is, it will increase by 4 times.

Answer: the kinetic energy of the body will also quadruple.