With full braking of the car, which had a speed of 20 m / s, it began to slide on the asphalt. The coefficient of friction of the wheels on the road is 0.4, its braking distance will be …
Initial data: V1 (the speed that the car had before braking) = 20 m / s; μ (coefficient of friction of the car wheels on the asphalt) = 0.4.
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
The braking distance of the car when sliding on asphalt is determined by the formula: S = (V2 ^ 2 – V1 ^ 2) / 2a, where V ^ 2 (final speed of the car) = 0 m / s; a (vehicle acceleration) = -μ * g (Ftr = μ * m * g = -m * a).
The formula will take the form: S = (-V1 ^ 2) / (2 * (-μ * g)).
Calculation: S = (-20 ^ 2) / (2 * (-0.4 * 10)) = 50 m.
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