With the complete oxidation of 12.3 g of nitrobenzene, 8.5 g of aniline was obtained

With the complete oxidation of 12.3 g of nitrobenzene, 8.5 g of aniline was obtained, calculate the yield from the theoretically possible.

Let’s execute the solution:
1. In accordance with the condition of the problem, we compose the equation:
m = 12.3 g. m = 8.5 g. W -?
C6H5NO2 + 3H2 = C6H5NH2 + 2H2O – reduction, aniline obtained;
2. Calculations:
M (C6H5NO2) = 123 g / mol;
M (C6H5NH2) = 93 g / mol;
Y (C6H5NO2) = m / M = 12.3 / 123 = 0.1 mol.
3. Find the theoretical mass for the product, the output from the theoretically possible:
m (C6H5NH2) = Y * M = 0.1 * 93 = 9.3 g;
W = m (practical) / m (theoretical) * 100;
W = 8.5 / 9.3 * 100 = 91.39%
Answer: the yield of aniline was 91.39%.