With what force will 2 electrons be repelled at a distance of 2 mm?

To calculate the repulsive force of taken electrons, we will use the Coulomb’s law: F = k * qe * qe / r ^ 2 = k * qe ^ 2 / r ^ 2.

Variables and constants: k – coefficient of proportionality (k = 9 * 10 ^ 9 N * m2 / Kl2); qe is the electron charge (qe = -1.6 * 10 ^ -19 C); r is the distance between electrons (r = 2 mm = 2 * 10 ^ -3 m).

Let’s perform the calculation: F = k * qe ^ 2 / r ^ 2 = 9 * 10 ^ 9 * (1.6 * 10 ^ -19) ^ 2 / (2 * 10 ^ -3) ^ 2 = 57.6 * 10 ^ -24 Cl = 57.6 iC.

Answer: The repulsive force of the taken electrons is 57.6 iC.