# Within 10 s, an amount of heat equal to 5 kJ was released in the conductor.

**Within 10 s, an amount of heat equal to 5 kJ was released in the conductor. What is the current if the resistance of the conductor is 1kom?**

Given:

Q = 15 kJ = 15000 Joules – the heat released in the conductor during the time interval t;

t = 10 seconds – time interval;

R = 1 kOhm = 1000 Ohm – conductor resistance.

It is required to determine I (Ampere) – the magnitude of the current.

The amount of heat will be equal to the work of the electric current performed during the time interval t:

Q = A = W * t = I * U * t.

Taking into account that U = R * I (Ohm’s law), we get:

Q = I * I * R * t = I ^ 2 * R * t, from here we find that:

I = (Q / (R * t) ^ 0.5 = (15000 / (1000 * 10) ^ 0.5 = (15000 / (10000) ^ 0.5 = 1.5 ^ 0.5 = 1.2 Ampere (result has been rounded to one decimal place).

Answer: the magnitude of the current strength is 1.2 Amperes.