The molecular formula of glucose is C₆H₁₂O₆.
The relative molecular weight of a substance is the mass of its molecule, expressed in atomic mass units. Let’s calculate the molecular weight of glucose.
Mr (C₆H₁₂O₆) = 6 * 12 + 12 * 1 + 6 * 16 = 180.
Let’s calculate the mass fraction of carbon.
ω (C) = 6 * 12/180 = 0.4 = 40%.
Let’s calculate the mass fraction of hydrogen.
ω (H) = 12 * 1/180 = 0.066 = 6.6%.
Let’s calculate the mass fraction of oxygen.
ω (O) = 6 * 16/180 = 0.534 = 53.4%.
Answer: Molecular weight C₆H₁₂O₆ = 180. ω (C) = 40%, ω (H) = 6.6%, ω (O) = 53.4%.
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