# Write down the molecular formula for glucose. Find its molecular weight and mass fraction of each element in% in it.

The molecular formula of glucose is C₆H₁₂O₆.

The relative molecular weight of a substance is the mass of its molecule, expressed in atomic mass units. Let’s calculate the molecular weight of glucose.

Mr (C₆H₁₂O₆) = 6 * 12 + 12 * 1 + 6 * 16 = 180.

Let’s calculate the mass fraction of carbon.

ω (C) = 6 * 12/180 = 0.4 = 40%.

Let’s calculate the mass fraction of hydrogen.

ω (H) = 12 * 1/180 = 0.066 = 6.6%.

Let’s calculate the mass fraction of oxygen.

ω (O) = 6 * 16/180 = 0.534 = 53.4%.

Answer: Molecular weight C₆H₁₂O₆ = 180. ω (C) = 40%, ω (H) = 6.6%, ω (O) = 53.4%.

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