Write the electrolysis reaction of sodium iodide solution.

NaI + 3H2O ± 6- → 3H2 + NaIO3
Electrolysis of an aqueous solution of sodium iodide to form hydrogen and sodium iodate.
Cathodic process: 6H + + 6e- → H2
Anodic process: I- + 3H2O – 6e- → IO3- + 6H +

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