Write the electronic balance equation SO2 + O2 = SO3.

S (+4) -2e = S (+6) – sulfur had an oxidation state of +4, in the process it donated two electrons and turned into sulfur with an oxidation state of +6; oxidation process, sulfur is a reducing agent;
O2 (0) + 4e = 2O (-2) – oxygen had an oxidation state of zero, after which it added two electrons and its oxidation state became -2; reduction process, oxygen is an oxidizing agent;
2SO2 + O2 = 2SO3

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