Write the equation of the straight line with the slope passing through the point A (3,1)

Write the equation of the straight line with the slope passing through the point A (3,1), perpendicular to the straight line 3y + x-4 = 0.

3 * y + x – 4 = 0;

Let us bring the equation to the form Y = k * X + b.

3 * Y = -X + 4;

Y = (-X / 3) + 0.75.

From the equation, the direct slope is equal to:

K = -1/3.

Lines are perpendicular if the product of their slopes is -1.

Then the slope of the second straight line is 3.

Equation of the second straight line: Y = 3 * X + b.

Substitute the coordinates of point A.

1 = 3 * 3 + b;

b = -8;

Y = 3 * X – 8.

Answer: The equation of the straight line Y = 3 * X – 8.

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