Write the reaction equation: Al-al2o3-alcl3-al (oh) 2-al2o3

Aluminum burns in oxygen to form alumina:

4 Al + 3 O2 = 2 Al2O3

Aluminum oxide, when interacting with hydrochloric acid, gives aluminum chloride and water:

Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O

Aluminum chloride when reacted with dilute alkalis gives a gelatinous precipitate of aluminum hydroxide / Or when interacting with an aqueous solution of alkali metal carbonates.

AlCl3 + 3 NaOH = Al (OH) 3 + 3 NaCl

2 AlCl3 + 3 К2CO3 + 3 H2O = 2 Al (OH) 3 + 6 КCl + 3 CO2

Aluminum hydroxide undergoes thermal decomposition when heated above 580 degrees with the formation of aluminum oxide and water.

Al (OH) 3 = Al2O3 + H2O