Aluminum burns in oxygen to form alumina:
4 Al + 3 O2 = 2 Al2O3
Aluminum oxide, when interacting with hydrochloric acid, gives aluminum chloride and water:
Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O
Aluminum chloride when reacted with dilute alkalis gives a gelatinous precipitate of aluminum hydroxide / Or when interacting with an aqueous solution of alkali metal carbonates.
AlCl3 + 3 NaOH = Al (OH) 3 + 3 NaCl
2 AlCl3 + 3 К2CO3 + 3 H2O = 2 Al (OH) 3 + 6 КCl + 3 CO2
Aluminum hydroxide undergoes thermal decomposition when heated above 580 degrees with the formation of aluminum oxide and water.
Al (OH) 3 = Al2O3 + H2O
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