Write the reaction equation: C- Al4C3- CH4- CO2- CaCO3- Ca (HCO3) 2 – CO2- CO

Let’s compose the equations, as well as the reaction conditions:
3C + 4Al = Al4C3 – the reaction of the compound, occurs when heated, aluminum carbide is obtained;
Al4C3 + 12H2O = 3CH4 + 4Al (OH) 3 – hydrolysis, the reaction proceeds under normal conditions, methane is released;
CH4 + 2O2 = CO2 + 2H2O – methane combustion occurs with the release of heat, carbon monoxide is formed (4);
CO2 + CaO = CaCO3 – the compound goes on heating:
CaCO3 + CO2 + H2O = Ca (HCO3) 2 – compounds, goes under normal conditions, calcium bicarbonate is obtained;
Ca (HCO3) 2 = CO2 + H2O + CaCO3 – decomposition possible when heated.
СО2 + С = 2СО – reduction with hot coal, carbon monoxide was obtained (2).

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