Write the reaction equation: CaCO3 – CaC2 – C2H2 – benzene – bromobenzene C2H2 – C2H4 – C2H5Cl – C4H10 – C4H9NO2
For the solution, we indicate the names of the substances:
Calcium carbonate – calcium carbide – acetylene – benzene – bromobenzene
CaCO3 + 4C = CaC2 + 3CO – OBP, calcium carbide was formed;
CaC2 + 2H2O = Ca (OH) 2 + C2H2 – hydration, acetylene obtained;
3C2H2 = C6H6 – trimerization, benzene is released;
C6H6 + Br2 = C6H5Br + HBr – substitutions, bromobenzene was formed.
The solution shows the relationship between inorganic and organic compounds using the example of calcium carbonate, benzene.
Acetylene – ethylene – chloroethane – butane – nitrobutane
C2H2 + H2 = H2C = CH2 – hydrogenation, ethylene was formed;
Н2С = СН2 + HCl = H3C – CH2Cl – addition, chloroethane is released;
2С2Н5Cl + 2Na = 2NaCl + C4H10 – butane obtained by the Wurtz reaction;
C4H10 + HNO3 = C4H9NO2 + H2O – nitration, nitrobutane was formed;
The reaction products have practical applications, for example, nitrobutane in the production of industrial explosives.