Write the reaction equation for the dehydrohalogenation of 2-bromobutane.

We write down the dehydrohalogenation reaction of 2-bromobutane, for this we add hydroxide to this compound of potassium.
CH3-CHBr-CH2-CH3 + KOH alcohol (t) = CH3-CH = CH-CH3 + KBr + H2O;
When 2 – bromobutane interacts with potassium hydroxide, the result is butene – 2, potassium bromide and water.

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