Write the reaction equations Al – AlCl3 – Al (OH) 3 – Al2O3 – Al2 (SO4) 3

1) 2Al + 6HCl = 2AlCl3 + 3H2 (gas).
2) AlCl3 + 3NaOH = 3NaCl + Al (OH) 3 (precipitate).
3) 2Al (OH) 3 = Al2O3 + 3H2O. This reaction takes place at a temperature of over 575 degrees Celsius.
4) Al2O3 + 3H2SO4 = Al2 (SO4) 3 + 3H2O.
Comment: the first chemical reaction by its type is a substitution reaction, the second is an exchange reaction; the third is the decomposition reaction; the fourth is the exchange reaction.

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